Monday, 13 January 2014

CONGRUENCE OF SIMPLE POLYGONS B8

In the figure below prove that DEH is congruent to GHF.




solution



Given: figure DEHGF .
Required to prove: DEH GHF
Proof: EH = HF (given)

            DH = HG (given)

          <EHD = <FHG (opposite angles)

Hence DEH GHF by SAS rule (proved)

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