Friday, 10 January 2014

LOGARITHMS B3



If log5(3x + 2)=2; find x.

   Solution

log5(3x + 1)=2
(3x + 1)=52      
                   
3x + 1=25

3x =25 – 1

3x = 24

2x = 24   
2        2

x = 12

Hence x = 12

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