Friday, 10 January 2014

LOGARITHMS B2




If log3(2x + 1)=2; find x

   Solution

log3(2x + 1)=2
 (2x + 1)=32    
                     
 2x + 1=9

2x =9 – 1

2x = 8

2x =   8   
2        2

x = 4

Hence x = 4

No comments:

Post a Comment