A number is chosen at random from 15
– 32 inclusive. Find the probability that it is a prime or a multiple of 2.
Solution
THIS IS A MUTUALLY EXCLUSIVE EVENT
Let n(S) represent sample space
P(M) = probability of a multiple of
2
P(R) = probability of prime number
n(S) = {15,16,17,18,19,20, 21, 22,
23, 24, 25, 26, 27, 28, 29, 30, 31, 32} = 18
n(M) = {22, 24, 26, 28, 30, 32 } = 9
n(R) = {17, 19, 23, 29, 31} = 5
P(M) = 6/18
P(R) = 5/18
………………………….
P(MuR) = P(M) + P(R)
P(MuR) = 6/18 + 5/18
= 11/18
Hence P(MuR) = 11/18 answer
TRY THIS…………………
A number is chosen at random from 19
– 30 inclusive. Find the probability that it is a prime number or a multiple of
5.
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