Caroline
invested a certain amount of money in a bank which gives an interest rate of
20% compounded annually. How much did she invest at the start if she got 6,000
sh at the end of 3 years?
Solution
n=3, t=1,
R=20%, A3=6,000, P=?
An
= P(1 + RT/100)n
A3
= P(1 + (20x1)/100)3
A3=
P(1 + 20/100)3
A3
= P(100/100 + 20/100)3
A3
= P(120/100)3 But
A3=6,000,
6,000 = P(1.2)3
= P(1.2x1.2x1.2)
6,000 = 1.728P
6000 = 1.728P
1.728 1.728
6000 = P
1.728
P = 3472.22
Hence at the start she invested Tsh 3472.22
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