Monday, 6 January 2014

STATISTICS B5



In Mathematics test the following marks were recorded.

marks
10-19
20-29
30-39
40-49
50-59
60-69
70-79
80-89
No. of students
4
6
9
10
13
8
7
3


Calculate the mean.

Solution

In this question we are going to apply the method of assumed mean.

Here you are required to produce the frequency distribution table.

Let us take 44.5 as our assumed mean (A). Take away the assumed mean from each class mark.


Class interval
Class mark (x)
d=x-A
Frequency(f)
fd
10-19
14.5
-30
4
-120
20-29
24.5
-20
6
-120
30-39
34.5
-10
9
-90
40-49
44.5
0
10
0
50-59
54.5
10
13
130
60-69
64.5
20
8
160
70-79
74.5
30
7
210
80-89
84.5
40
3
120


∑f = 60
∑fd = 290


Mean = A +  fd
                      ∑f

Mean = 44.5 +  290
                          60

Mean = 44.5 +  (4.83)
                    
Mean = 49.33   (to 2d.p)
         
Hence Mean =  49.33
                

No comments:

Post a Comment