If
log_{9}(32x + 17)=2; find x.
Solution
Log_{9}(32x
+ 17)=2
(32x + 17)=9^{2 }
^{ }
32x
+ 17=81
32x
=81 – 17
32x
= 64
32x = 64
32 32
x = 2
Hence x = 2
TRY THIS………………
If
log_{7}(2t - 65)=2; find t