Tuesday, 14 January 2014

FUNCTIONS B7

If F(x) = log2x, Find F(128)

Solution

F(x) = log2x

F(128)= log2(128)

F(128)= log227

F(128)= 7log22

F(128)= 7 x 1

F(1/32) = 7

Therefore F(128)= 7

No comments:

Post a Comment