Tuesday 17 July 2018

PROBABILITY 1



A number is chosen at random from 1 – 15 inclusive. Find the probability that it is a multiple of five or an even number.

Solution

THIS IS A NON-MUTUALLY EXCLUSIVE EVENT.

Let n(S) represent sample space
P(E) = probability of even number
P(M) = probability of a multiple of 5

n(S) = {1, 2, 3, 4, 5, 6, 7, 8, 9,10, 11, 12, 13, 14, 15} = 15
n(E) = {2, 4, 6, 8, 10, 12, 14} = 7
n(M) = {5, 10, 15 } = 3
But 14 appears on both categories.
P(E) = 7/15
P(M) = 3/15
P(EnM) = 1/15
………………………….
P(EuM) = P(E) + P(M) - P(EnM) 

P(EuM) = 7/15 + 3/15 -1/15

            = 9/15

            = 3/5

P(EuM) = 3/5

TRY THIS………………


A number is chosen at random from 4 – 30 inclusive. Find the probability that it is a multiple of 5 or an even number. 



No comments:

Post a Comment