Distribution
of Kiswahili test marks was given as heeunder.
Length(mm)
|
10 - 19
|
20- 29
|
30 - 39
|
40 - 49
|
50 - 59
|
60 - 69
|
70 - 79
|
Frequency
|
4
|
6
|
10
|
14
|
8
|
5
|
3
|
Calculate
the median.
Solution
First we
prepare the frequency distribution table.
Class interval
|
Frequency(f)
|
Cumulative frequency
|
10-19
|
4
|
4
|
20-29
|
6
|
10
|
30-39
|
10
|
20
|
40-49
|
14
|
34
|
50-59
|
8
|
42
|
60-69
|
5
|
47
|
70-79
|
3
|
50
|
∑f = 50
|
N = 50,
N/2=25, Median class must fall in the cumulative frequency of 25. This has to
be 40 – 49.
nb
= 20, nw = 14, Upper boundary(U)= 49.5, Lower boundary(L) =39.5
i = Upper boundary – Lower boundary
i = 49.5 –
39.5
i = 10
Median = L + (N/2 – nb)i/nw
Median = 39.5 + (50/2 –
20)10
14
Median = 39.5 + (25 – 20)10
14
Median = 39.5 + (5)10
14
Median = 39.5 + 50
14
Median = 39.5 + 3.57
Median = 43.07
Hence median is 43.07
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