Evaluate Log2(4
x 16).
Solution
= Log2(4 x 16)
= Log24 + Log216 (applying the product rule)
= Log222
+ Log224 ( 4= 22 and 16=24
)
= 2Log22 + 4Log22 ( remember Logaac = cLogaa
)
= (2 x 1) + (4 x 1) ( remember Logaa = 1 )
= 2 + 4
= 6
hence Log2(4 x 16) = 6
No comments:
Post a Comment