If
F(x) = log2x, Find F(1/64)
Solution
F(x)
= log2x
F(1/32)
= log2(1/64)
F(1/32)
= log264-1
F(1/32)
= log2(26)-1
F(1/32)
= log22(6 x -1)
F(1/32)
= log22-6
F(1/32)
= -6log22
F(1/32)
= -6 x 1
F(1/32)
= -6
Therefore F(1/32)
= -6
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