Tuesday 7 January 2014

STATISTICS B7




Distribution of Biology test marks was given as hereunder.

Length(mm)
15 - 19
20- 24
25 - 29
30 - 34
35 - 39
40 - 44
45 - 49
Frequency
3
5
9
12
6
3
2

Calculate the median.

Solution

First we prepare the frequency distribution table.

Class interval
Frequency(f)
Cumulative frequency
15-19
3
3
20- 24
5
8
25 - 29
9
17
30 - 34
12
29
35 - 39
6
35
40 - 44
3
38
45 - 49
2
40

∑f = 40


N = 40, N/2=20, Median class must fall in the cumulative frequency of 20. This has to be 30 – 34.

nb = 17, nw = 12, Upper boundary(U)= 34.5, Lower boundary(L) =29.5

 i = Upper boundary – Lower boundary
i = 34.5 – 29.5
i = 5

Median = L + (N/2 – nb)i/nw
                              

Median = 29.5 + (40/2 – 17)5
                                     12

Median = 29.5 + (20 – 17)5
                                  12

Median = 29.5 + (3)5
                             12

  Median = 29.5 + 15
                             12

  Median = 29.5 +  1.25
                               
 Median = 30.75

Hence the median is 30.75                      

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