Distribution
of Biology test marks was given as hereunder.
Length(mm)
|
15 - 19
|
20- 24
|
25 - 29
|
30 - 34
|
35 - 39
|
40 - 44
|
45 - 49
|
Frequency
|
3
|
5
|
9
|
12
|
6
|
3
|
2
|
Calculate
the median.
Solution
First we
prepare the frequency distribution table.
Class interval
|
Frequency(f)
|
Cumulative frequency
|
15-19
|
3
|
3
|
20- 24
|
5
|
8
|
25 - 29
|
9
|
17
|
30 - 34
|
12
|
29
|
35 - 39
|
6
|
35
|
40 - 44
|
3
|
38
|
45 - 49
|
2
|
40
|
∑f = 40
|
N = 40,
N/2=20, Median class must fall in the cumulative frequency of 20. This has to
be 30 – 34.
nb
= 17, nw = 12, Upper boundary(U)= 34.5, Lower boundary(L) =29.5
i = Upper boundary – Lower boundary
i = 34.5 –
29.5
i = 5
Median = L + (N/2 – nb)i/nw
Median = 29.5 + (40/2 –
17)5
12
Median = 29.5 + (20 – 17)5
12
Median = 29.5 + (3)5
12
Median = 29.5 + 15
12
Median = 29.5 + 1.25
Median = 30.75
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