If Log[(30x-70)/(5+x)] = 1. Find x.
Solution
Log[(30x-70)/(5+x)] = 1.
Log10[(30x-70)/(5+x)] = 1.
30x-70 = 101. After changing
into exponential form
5+x
30x-70 = 10 since [101=10]
5+x
30x-70 = 10(5+x) after cross multiply
30x-70 = 50+10x
30x-10x = 50+70 [collecting
like terms]
20x = 120
x=6 [after dividing by 20 both sides]
Hence x=6.
TRY THIS……………
If Log[(2x+4)/(x-2)] = 1. Find x.
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