LOGARITHMS 21

If log 2= 0.3010; find the value of log 1250 without using tables.

Solution

=log1250

=log(10,000 ÷8)

=log10,000 –log8

= log10⁴ - log2³

= 4log10 - 3log2

=(4 x 1) - (3 x 0.3010)

= 4  -  0.9030

=3.097

Hence log 1250 =3.097

TRY THIS……………

If log 2= 0.3010; find the value of log 2500 without using tables.