ALGEBRA 5

The sum of four consecutive numbers is 1222. Find the 4th number.

Solution

Let the numbers be as shown in the table below

1st number	2nd number	3rd number	4th number	TOTAL
n	n+1	n+2	n+3	1222

Then, n + (n+1) + (n+2) + (n+3) = 362

4n + 1+2+3= 1222

4n + 6 = 1222

4n = 1222 – 6

4n = 1216

4n = 1216

 4        4

n = 304

4th number = n + 3

                  = 304 + 3

                  = 307

Hence the 4th number is 307

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The sum of four consecutive numbers is 774. Find the 3rd number.

The sum of four consecutive numbers is 362. Find the 4th number.