If
(x4)(y2) = 2500; find x and y.
solution
(x4)(y2)
= 2500 [500=2x2x5x5x5 by prime
factorization].
(x4)(y2)
= (54 )x (22) [
since 2500=54 x 22].
equating
equal powers,
(x4) = (54)
x = 5 [equal
powers will cancel out]
also,
(y2)
= (22)
y
= 2 [equal powers will cancel out]
∴
x =
5 and y = 2
TRY THIS…………
If
(x3)(y5) = 1944; find x and y.
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