Thursday, 13 July 2017

FUNCTIONS 5


If f(x) = x4 + kx2 + 6x + 7 has a remainder of 24 when divided by x+2; find k.

solution

f(x) = x4 + kx2 + 6x + 7

x + 2 = 0

x = -2

f(x) = (-2)4 + k(-2)2 + 6(-2) + 7 = 24

16 + 4k + (-12) + 7 = 24

16 + 4k - 12 + 7 = 24

16 + 4k - 5 = 24

4k + 16 - 5 = 24

4k + 11= 24

4k = 24 - 11

4k = 13

4k = 13
4      4

k = 13/4

hence k=13/4

TRY THIS......................



If f(x) = x4 - kx2 + 3x - 11 has a remainder of 12 when divided by x+3; find k.

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