CONGRUENCE 1

In the figure below, prove that ΔEFG and ΔGEH  are congruent. 

Solution

GIVEN: Quadrilateral EFGH,

                EF=GH,

              <FGE=<GEH

REQUIRED TO PROVE: ΔEFG ≡ΔEGH.

PROOF:  EG=GE             (given)

                 <FGE=<GEH    (given)

                  EG= GE           (common)

Hence ΔEFG ≡ΔEGH  (By SAS)

TRY THIS…………………

In the figure below, prove that ΔSTU and ΔUSV are congruent.