PROBABILITY 1

The probability that Azam FC will beat Yanga in the national league is ⁹/11. Find the probability that it won’t be able to do so.

Solution

Let P(E)=  ⁹/11         P(E’) = ?

P(E)   + P(E’) = 1

⁹/11 + P(E’) = 1

P(E’) = 1 -  ⁹/11

P(E’) = ¹¹/11 -  ⁹/11

P(E’) =  11-9

               11

P (E’) =  2

             11

Hence answer is ²/11.

TRY THIS…………………………

The probability that Mtibwa FC will beat Mbeya City FC in the national league is ¹³/30. Find the probability that it won’t be able to do so.