Monday, 10 July 2017

ARITH. PROGRESSION 1


The 1st term of arithmetic progression is 12 and the common difference is 50. Find the 7th term

solution

A= 12, d = 50, n = 7, A7 = ?

An = A1 + (n-1)d

A= A1 + (7-1)d

A= A1 + 6d

A= 12 + (6x50)

A= 12+300

A= 312

Hence the 7th term is 312

TRY THIS………………………………


The 1st term of arithmetic progression is 7 and the common difference is 30. Find the 11th term

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