The
1st term of arithmetic progression is 12 and the common difference is 50. Find
the 7th term
solution
A1 = 12, d = 50, n = 7, A7 = ?
An
= A1 + (n-1)d
A7 = A1 + (7-1)d
A7 = A1 + 6d
A7 = 12 + (6x50)
A7 = 12+300
A7 = 312
Hence the 7th term is 312
TRY THIS………………………………
The
1st term of arithmetic progression is 7 and the common difference is 30. Find
the 11th term
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