Saturday, 26 November 2016

LOGARITHMS 20


If logx3125 – log3729 = -1; find x

solution

logx3125 – log3729 = -1

logx3125 – log336 = -1

logx3125 – 6log33 = -1

logx3125 – 6 x 1 = -1

logx3125 – 6 = -1

logx3125 = -1 + 6

logx3125 = 5

3125 = x5

55 = x5      Powers cancel out

x = 5
  
Hence x = 5.

TRY THIS………….


If logk1024 – log7343 = 7; find k

No comments:

Post a Comment