MATHEMATICS PROBLEM SOLVER

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Monday, 10 July 2017

LOGARITHMS 11

If F(x) = log₂x, Find F(¹/₁₂₈)

Solution

F(x) = log₂x

F(¹/₃₂) = log₂(¹/₁₂₈)

F(¹/₃₂) = log₂128^-1

F(¹/₃₂) = log₂(2⁷)^-1

F(¹/₃₂) = log₂2⁽⁷ ^x ^-1)

F(¹/₃₂) = log₂2^-7

F(¹/₃₂) = -7log₂2

F(¹/₃₂) = -7 x 1

F(¹/₃₂) = -7

Therefore F(¹/128) = -7

TRY THIS………………………………

If F(x) = log₂x, Find F(¹/₃₂)

MATHEMATICS PROBLEM SOLVER

Monday, 10 July 2017

LOGARITHMS 11

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