If F(x) = log2x,
Find F(1/128)
Solution
F(x) = log2x
F(1/32)
= log2(1/128)
F(1/32)
= log2128-1
F(1/32)
= log2(27)-1
F(1/32)
= log22(7 x -1)
F(1/32)
= log22-7
F(1/32)
= -7log22
F(1/32)
= -7 x 1
F(1/32)
= -7
Therefore F(1/128) = -7
TRY THIS………………………………
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