A bag contains 10 red balls
and 8 blue balls. Two balls are taken from the bag. What is the probability
that they are both blue?
Solution
(This is a problem with
replacement)
n(R) = 10, n(B) = 8, n(S) =
18
P(B) = n(B)
n(S)
1st pick = 8/18
2nd pick = 8/18 as well.
P(B) = 8 x
8
18 18
P(B) = 324
= 16
196 81
Therefore Probability
of drawing a blue ball is 16/81
TRY THIS
..............
A bag contains 8 purple
stones and 12 blue stones. Two stones are taken from the bag. What is the
probability that they are both blue?
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