Tuesday, 15 November 2016

SETS 5


If n(A)= 70 , n(B)= 90 and n(AuB)= 130, find n(AnB).

Solution

n(AuB) = n(A) + n(B) - n(AnB)

130 = 70 + 90 - n(AnB)

130 = 160 - n(AnB)

130 - 160 = - n(AnB)

-30 = -n(AnB)

n(AnB) = 30 [after dividing by -1 both sides]

Hence n(AnB) = 30 answer


TRY THIS………….



If n(A)= 71 , n(B)= 88 and n(AuB)= 130, find n(AnB).

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