The
slope of a line which passes through (-5, -12) and (c,-9) is 3/11.
Find c.
Solution
x1
= -5, y1 =-12, x2 = c, y2 =
-9
m
= y2 –y1
x2 – x1
3 =
-9 –(-12)
11 c –(-5)
3 =
-9 + 12
11 c + 5
3 =
3 .
11
c + 5
3(c
+ 5) = 3 x 11 [after cross
multiplying]
3c
+ 15 = 33
3c
= 33 - 15
3c
= 18
3c = 18
3 3
c
= 6 [after dividing by 3 both sides]
Hence the slope is 3/11
TRY
THIS………………..
The
slope of a line which passes through (-4, -14) and (e,-7) is 3/10.
Find e.
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