Thursday, 17 November 2016

FUNCTIONS 9

If F(x) = log5x, Find F(1/3125)

Solution

F(x) = log5x

F(1/3125) = log5(1/3125)

F(1/3125) = log33125-1

F(1/3125) = log5(55)-1

F(1/3125) = log55(5 x -1)

F(1/3125) = log55-5

F(1/3125) = -5log55

F(1/3125) = -5 x 1

F(1/3125) = -5


Therefore F(1/3125) = -5

TRY THIS...............


If F(x) = log3x, Find F(1/729)

1 comment:

  1. Owen you must be intelligent. I can see that you got it right. Thanks a lot for visiting this place. Welcome again and again.

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