If F(x) = log5x, Find F(1/3125)
Solution
F(x) = log5x
F(1/3125) =
log5(1/3125)
F(1/3125) =
log33125-1
F(1/3125) =
log5(55)-1
F(1/3125) =
log55(5 x -1)
F(1/3125) =
log55-5
F(1/3125) = -5log55
F(1/3125) = -5
x 1
F(1/3125) = -5
Therefore F(1/3125)
= -5
TRY
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If F(x) = log3x, Find F(1/729)
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