A line passes through (2a, 9)
and (8,5a). If its slope is 10, find a.
Solution
x1=2a, y1 = 9, x2 = 8, y2 =
5a
Slope(m) = y2
– y1
x2 – x1
10 = 5a – 9
8 – 2a
10 = 5a – 9 [cross
multiplying]
1 8 – 2a
10(8 – 2a) = 5a – 9
80 – 20a = 5a – 9
80 – 8a + 9 = 5a
80 + 9 = 5a+ 8a
89 = 13a
89 = 13a
13 13
a= 89/13
a= 6 11/13
Hence a= 6 11/13
TRY THIS…………………..
A line passes through (2a, 9)
and (3,5a). If its slope is 20, find a.
No comments:
Post a Comment