Evaluate
Log2(256 x 128).
Solution
=
Log2(256 x 128)
=
Log2256 + Log2128
(applying the product rule)
=
Log228 + Log227
( 256= 28 and 128=27
)
=
8Log22 + 7Log22
( remember Logaac = cLogaa )
=
(8 x 1) + (7 x 1) (
remember Logaa = 1 )
=
8 + 7
=
15
hence
Log2(256 x 128) = 15
TRY THIS...............
No comments:
Post a Comment