Thursday, 17 November 2016

LOGARITHMS 14


Evaluate Log2(256 x 128).

Solution

= Log2(256 x 128)

= Log2256 +  Log2128          (applying the product rule)

= Log228 +  Log227             ( 256= 28 and 128=27 )

= 8Log22 +  7Log22       ( remember  Logaac = cLogaa )

= (8 x 1) +  (7 x 1)          ( remember  Logaa = 1 )

= 8 + 7

= 15
  
hence Log2(256 x 128) = 15

TRY THIS...............

Evaluate Log2(4096 x 128). 

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