Saturday, 12 November 2016

FUNCTIONS 5


If F(x) = log2x, Find F(1/4096)

Solution

F(x) = log2x

F(1/4096) = log2(1/4096)

F(1/4096) = log24096-1

F(1/4096) = log2(212)-1

F(1/4096) = log22(12 x -1)

F(1/4096) = log22-12

F(1/4096) = -12log22

F(1/4096) = -12 x 1

F(1/4096) = -12

Therefore F(1/4096) = -12


TRY THIS…………………


If F(x) = log2x, Find F(1/8192)
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