SETS 1

If n(B)= 60 , n(AuB) = 160 and n(AnB)=10, find n(A)

Solution

n(AuB) = n(A) + n(B) - n(AnB)

  160     = n(A)  + 60– 10

  160     = 60 -10 + n(A) 

  160     = 50 + n(A) 

  160 - 50        = n(A)

  110        = n(A)

Hence n(A) = 110 answer

TRY THIS…………………………….

If n(B)= 60 , n(AuB) = 160 and n(AnB)=10, find n(A)