In a certain exam the
following marks were recorded.
marks
|
10-14
|
15-19
|
20-24
|
25-29
|
30-34
|
35-39
|
40-44
|
45-49
|
No. of students
|
4
|
8
|
9
|
13
|
11
|
8
|
4
|
3
|
Calculate the mean.
Solution
In this question we are
going to apply the method of assumed mean.
Here you are required to
produce the frequency distribution table.
Let us take 27 as our
assumed mean (A). Take away the assumed mean from each class mark.
Class interval
|
Class mark (x)
|
d=x-A
|
Frequency(f)
|
fd
|
10-14
|
12
|
-15
|
4
|
-60
|
15-19
|
17
|
-10
|
8
|
-80
|
20-24
|
22
|
-5
|
9
|
-45
|
25-29
|
27
|
0
|
13
|
0
|
30-34
|
32
|
5
|
11
|
55
|
35-39
|
37
|
10
|
8
|
80
|
40-44
|
42
|
15
|
4
|
60
|
45-49
|
47
|
20
|
3
|
60
|
|
|
∑f = 60
|
∑fd = 70
|
Mean = A + ∑fd
∑f
Mean = 27 + (70)
60
Mean = 27 + (1.167)
Mean = 28.17 (to 2d.p)
Hence Mean = 28.17
TRY THIS……………………..
In a certain exam the following marks were
recorded.
marks
|
10-14
|
15-19
|
20-24
|
25-29
|
30-34
|
35-39
|
40-44
|
45-49
|
No. of students
|
4
|
7
|
10
|
14
|
11
|
8
|
5
|
3
|
Calculate the mean.
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