Tuesday, 25 February 2014

LOGARITHMS B35

If logx27 + log2256 = 11; find x

solution

logx27 + log2256 = 11

logx27 + log228 = 11

logx27 + 8log22 = 11

logx27 + 8 x 1 = 11

logx27 + 8 = 11

logx27 = 11- 8

logx27 = 3

27 = x3

33 = x3      Powers cancel out

x = 3


Hence x = 3.
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