Solution
Given : A circle with centre O and the angles ∠WYX and
∠WZX in the same segment formed by
the chord WX (or arc WAX)
Required to prove: ∠WYX = ∠WZX
Construction : Join OW and OX.
Proof :
Try to remember that angle subtended by an arc at the centre is double the angle subtended by it at any point on the remaining part of the circle, hence we have,
∠WOX = 2∠WYX ...............(i)
and,
∠WOX= 2∠WZX …………...(ii)
Since (i) = (ii), we get,
2∠WYX = 2∠WZX
2∠WYX = 2∠WZX (dividing by 2 both sides)
2 2
∠WYX = ∠WZX
∴ ∠WYX =∠WZX proved!
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