The 1st term
of an A.P. is 67 and the common difference is 24. Find the 10th term.
Solution
A1=
67, d = 24
An
= A1 + (n-1)d
A10
= A1 + (10-1)d
A10
= A1 + 9d
A10
= 67 + (9x24) [ after substituting A1= 67, d = 24 as given above]
∴ A10 = 67 + 216
A10
= 283
Hence the 10th term is 283.
TRY THIS……………
The 1st term
of an A.P. is 100 and the common difference is 27. Find the 6th term.
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