If
F(x) = log2x, Find F(1/512)
Solution
F(x)
= log2x
F(1/32)
= log2(1/512)
F(1/32)
= log2512-1
F(1/32)
= log2(29)-1
F(1/32)
= log22(9 x -1)
F(1/32)
= log22-9
F(1/32)
= -9log22
F(1/32)
= -9 x 1
F(1/32)
= -9
Therefore F(1/32)
= -9
TRY THIS…………………
If
F(x) = log2x, Find F(1/256)
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