If
F(x) = log3x, Find F(243)
Solution
F(x)
= log3x
F(243)=
log3(243)
F(243)=
log335
F(243)=
5log33
F(243)=
5 x 1
F(243)
= 5
Therefore F(243) = 5
TRY THIS...........
If F(x) = log3x, Find F(1/729)
TRY THIS...........
If F(x) = log3x, Find F(1/729)
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