LOGARITHMS B12

Evaluate Log₂(8 x 32).

Solution

= Log₂(8 x 32)

= Log₂8 +  Log₂32          (applying the product rule)

= Log₂2³ +  Log₂2⁵             ( 8= 2³ and 32=2⁵ )

= 3Log₂2 +  5Log₂2       ( remember  Log_aa^c = cLog_aa )

= (3 x 1) +  (5 x 1)          ( remember  Log_aa = 1 )

= 3 + 5

= 8

hence Log₂(8 x 32) = 8 

TRY THIS.......

Evaluate Log₂(16 x 8).