A bag
contains 6 red stones and 8 blue stones. Two balls are taken from the bag. What
is the probability that they are both red?
Solution
(This is a problem with
replacement)
n(R) = 6, n(B) = 8, n(S) =
14
P(R) = n(R)
n(S)
1st pick = 6/14
2nd pick = 6/14 as well.
P(R) = 6 x 6
14 14
P(R) = 36
= 4
196
49
Therefore Probability of drawing a
red stone is 4/49
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