A bag
contains 6 red balls and 8 blue balls. Two balls are taken from the bag. What
is the probability that they are both blue?
Solution
(This is a problem with
replacement)
n(R) = 6, n(B) = 8, n(S) =
14
P(B) = n(B)
n(S)
1st pick = 8/14
2nd pick = 8/14 as well.
P(B) = 6 x 6
14 14
P(B) = 36
= 4
196 49
Therefore Probability of drawing a blue
ball is 4/49
TRY THIS ..............
A bag contains 10 purple stones and 12 blue stones. Two stones are taken from the bag. What is the probability that they are both blue?
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