If zx2 - 8x + 1
= 0 is a perfect square, find the value of z .
Solution
In zx2 - 8x + 1
= 0; a=z, b=(-8) and c=1.
For the perfect square, b2
= 4ac
(-8)2 = 4 x z x
1
64 = 4z
64 = 4z
4 4
16 = z
Hence the value of z is 16
TRY THIS......
If zx2 - 16x + 4 = 0 is a perfect square, find the value of z .
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