PERFECT SQUARES B1

If zx² - 8x + 1 = 0 is a perfect square, find the value of z .

Solution

In zx² - 8x + 1 = 0;   a=z, b=(-8) and c=1.

For the perfect square, b² = 4ac

(-8)² = 4 x z x 1

64 = 4z

64 =  4z

 4      4

16 = z

Hence the value of z is 16

TRY THIS......

If zx² - 16x + 4 = 0 is a perfect square, find the value of z .