Monday, 24 February 2014

LOGARITHMS B33

If logx625 + log327 = 7; find x

solution

logx625 + log327 = 7

logx625 + log333 = 7

logx625 + 3log33 = 7

logx625 + 3 x 1 = 7

logx625 + 3 = 7

logx625 = 7- 3

logx625 = 4

625 = x4

54 = x4      Powers cancel out

x = 5


Hence x = 5.

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