Tuesday 18 March 2014

LOGARITHMS B12



If log5(2x + 1)=2; find x.

   Solution

log5(2x + 1)=2
(2x + 1)=52     
                    
2x + 1=25

2x =25 – 1

2x = 24

2x =   24   
2        2

X = 12

Hence x = 12

TRY THIS………………

If log7(2t + 1)=2; find t

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