ARITHMETIC PROGRESSION - 2

Find the general term of an A. P. which has the 1st term of -62 and common difference of 88.

Solution

A₁ = -62, d= 88, n = n.

A_n = A₁ + (n-1)d

     = -62 + (n-1)88

     = -62 +  88n-88

     = 88n -88-62

     = 88n - 150       [ since -88-62= -150 ]

∴  A_n = 88n - 150

Hence the general term is 88n- 150.

TRY THIS…………………………..

Find the general term of an A. P. which has the 1st term of 60 and common difference of 33.