Wednesday, 2 December 2015

LOGARITHMIC EQUATIONS 1




If log3(3x + 39)=3; find x

   Solution

log3(3x + 39)=3

 (3x + 39)=33   
                      
 3x + 39=27


3x = 27 – 39

3x =  -12


3x =  -12   
3        3

X = -4


Hence x = -4

TRY THIS...............

If log2(3x - 31)=5; find x

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