If F(x) =
log5x, Find F(1/125)
Solution
F(x) = log5x
F(1/125)
= log5(1/125)
F(1/125)
= log3125-1
F(1/125)
= log5(53)-1
F(1/125)
= log55(3 x -1)
F(1/125)
= log55-3
F(1/125)
= -3log55
F(1/125)
= -3 x 1
F(1/125)
= -3
Therefore
F(1/125) = - 3
TRY THIS...............
If F(x) =
log3x, Find F(1/729)
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