AXIS OF SYMMETRY 5

Find the axis of symmetry for F(x) = 6x² + 40x + 8

Solution

a=6, b=40

Axis of symmetry = -b/2a

                                  =  -(40)

                                       2 x 6

                                 =    -40

                                         12

                                 =   -10

                                         3

Hence the axis of symmetry is ^-10/3

TRY THIS...............

Find the axis of symmetry for F(x) = 5x² + 70x + 8