MATHEMATICS PROBLEM SOLVER

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Saturday, 4 April 2015

LOGARITHMS 5

If Log_b125 – log0.00001 = 8; find b

Solution

Log_b125 – log0.001 = 6; [0.00001=10^-5]

Log_b125 – log10^-3= 6

Log_b125 – (-3log10)= 6

Log_b125 + 3log10= 6 [remember log 10 = 1]

Log_b125 + (3 x 1) = 6

Log_b125 + 3 = 6

Log_b125 = 6 - 3

Log_b125 = 3 [Change it into exponential notation]

125 = b³

5³ = b³[ bases are same on both sides, so they cancel out ]

b = 5

Hence b = 5

TRY THIS..............

If Log_b64 – log0.00001 = 11; find b

MATHEMATICS PROBLEM SOLVER

Saturday, 4 April 2015

LOGARITHMS 5

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