A line passes through
(2a, 7) and (8, 5a). If its slope is 2, find a.
Solution
x1=2a, y1 = 7, x2 = 8,
y2 = 5a
Slope(m) =
y2 – y1
x2 – x1
2 = 5a – 7
8 – 2a
2 = 5a – 7
[cross multiplying]
1
8 – 2a
2(8 – 2a) = 5a – 7
16 – 4a = 5a – 7
16 – 8a + 7 = 5a
16 + 7 = 5a+ 8a
23 = 13a
23 = 13a
13 13
23/13 = a
Hence a = 23/13
TRY
THIS.................................
A line passes through
(2a, 7) and (1, 4a). If its slope is 8, find a.
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