Wednesday, 8 April 2015

LOGARITHMIC FUNCTIONS 1




If F(x) = log5x, Find F(1/3125)

Solution

F(x) = log5x

F(1/3125) = log5(1/3125)

F(1/3125) = log53125-1

F(1/3125) = log5(55)-1

F(1/3125) = log55(5 x -1)

F(1/3125) = log55-5

F(1/3125) = -5log55

F(1/3125) = -5 x 1

F(1/3125) = -5


Therefore F(1/3125) = -5

TRY THIS...............

If F(x) = log3x, Find F(1/6561)

Posted by at

No comments:

Post a Comment

Subscribe to: Post Comments (Atom)